捉双：后到e5 (e7)
li-07REZ命名标签 (格·N)战术主题
捉双：一子同时攻击两个目标——无法两全。
难度2052 ShuffleRating——专家水平——很少有人一次解出。
黑方走棋——找出最佳续着
How to recognize this tactic
A fork is one piece attacking two targets at once. Look for a knight, pawn or queen move that lands where it hits the king (or a bigger piece) and a second undefended unit on the same turn — the opponent can save only one.
General method: before you move, list the forcing candidates — every check, every capture, every direct threat — and calculate those first. The solution to a tactic is almost always among them.
棋盘上的局面
白方：王 g1, 后 a4, 车 a1 d1, 象 g2 e3, 马 b1, 兵 h2 a3 d3 g3 c4 e5。
黑方：王 b8, 后 e7, 车 d8 h8, 象 b7 f8, 马 g8, 兵 b4 b6 h6 a7 c7 g7。
棋盘上有13枚白棋和13枚黑棋；该题局面出现在第19回合之后。
The position in numbers
Material is level — 34 points of pieces on each side (pawn = 1, knight and bishop = 3, rook = 5, queen = 9).
The white king stands on g1, the black king on b8.
It is Black to move on move 19, with 39 legal replies to weigh — only the line that keeps the advantage solves the puzzle.
White keeps 6 pawns, Black 6. Files fully open (no pawns of either colour): f — natural highways for the rooks and queen. Half-open for Black: d, e.
The Black king has 2 empty squares to step to right now — the fewer they are, the closer a mating net.
解答与讲解
主要变着
19... Qxe5 20. Bxb6 cxb6
为何奏效
- 好棋！后到e5保持压力（+2.7）。
- 好棋！兵到b6保持压力（+3.1）。
- 你赢得一子——象。
- 若改走Bxb6，则cxb6，你赢得象。
Move by move
- 19… Qxe5 — 后 to e5 (capture)
- 20. Bxb6 — 象 to b6 (capture)
- cxb6 — 兵 to b6 (capture)
本题的题型
制胜一击
找到那记强制得子的妙击。
制胜一击：强制赢得子力，却不归入任何单一的教科书主题。通用的战术配方在此适用：找出无保护的棋子、站位别扭的国王、超载的线路。按力度顺序枚举强制着法：将军、吃子、威胁——绝大多数组合正是从其中之一开始。不要凭感觉评估：把具体变化算到结果确凿无疑为止。
来源
源自 Lichess 题库（CC0）。
经 Stockfish 深度 20+ 验证。
解法强制性已确认（verified）。
题包 014
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