捉双：马到f3 (d4·4)
li-0KRbD命名标签 (格·N)战术主题
捉双：一子同时攻击两个目标——无法两全。
牵制：棋子一动，身后更有价值的目标就会暴露。
难度2080 ShuffleRating——专家水平——很少有人一次解出。
黑方走棋——找出最佳续着
How to recognize this tactic
A fork is one piece attacking two targets at once. Look for a knight, pawn or queen move that lands where it hits the king (or a bigger piece) and a second undefended unit on the same turn — the opponent can save only one.
A pin freezes a piece in front of a more valuable one behind it. Scan the ranks, files and diagonals your bishop, rook or queen controls: if an enemy piece cannot move without exposing its king or queen, it is pinned and can be piled on or bypassed.
General method: before you move, list the forcing candidates — every check, every capture, every direct threat — and calculate those first. The solution to a tactic is almost always among them.
棋盘上的局面
白方：王 h2, 后 d2, 车 e3 g3, 兵 a2 b2 c2 f2 d3 f3 h4。
黑方：王 c8, 后 f4, 车 d6, 马 d4, 兵 e5 h5 a7 b7 c7 g7。
棋盘上有11枚白棋和10枚黑棋；该题局面出现在第23回合之后。
The position in numbers
White are ahead by 3 points of material (26 against 23; pawn = 1, knight and bishop = 3, rook = 5, queen = 9) — the tactic has to convert or outweigh that.
The white king stands on h2, the black king on c8.
It is Black to move on move 23, with 42 legal replies to weigh — only the line that keeps the advantage solves the puzzle.
White keeps 7 pawns, Black 6. No file is fully open, so the heavy pieces have to be pried in. Half-open for Black: d, f.
The Black king has 3 empty squares to step to right now — the fewer they are, the closer a mating net.
解答与讲解
主要变着
23... Nxf3+ 24. Rxf3 Qxd2
为何奏效
- 好棋！马到f3保持压力（+5.1）。
- 好棋！后到d2保持压力（+5.1）。
- 你赢得一子——后。
- 若改走Rxf3，则Qxd2，你赢得后。
Move by move
- 23… Nxf3+ — 马 to f3 (capture) with check
- 24. Rxf3 — 车 to f3 (capture)
- Qxd2 — 后 to d2 (capture)
本题的题型
王室捉双
带将军的捉双：王必须躲开，另一个子就丢了。
王家捉双是带将军的捉双：两个目标之一是国王本身。国王必须首先应将，因此没有人、也没有时间去救第二个棋子。寻找这样的格子：你的棋子从那里将军，同时攻击无保护的后或车。这是最可靠的捉双——对手根本没有选择的余地。
来源
源自 Lichess 题库（CC0）。
题包 015
相似题目
在浏览器或 Android 应用中。无需安装 · 免费，无广告